Python有与reinterpret_cast类同的机制吗

嗯这里“类似”不是指和 C++ 的 reinterpret_cast 一模一样，是这个意思：

假设我有以下两个类：

class Point1(object):

    def __init__(self, x, y):
        (self._x, self._y) = (x, y)

    def __str__(self):
        return "(%d, %d)" % (x, y)


class Point2(object):

    def __init__(self, y, x):
        (self._x, self._y) = (x, y)

    def __str__(self):
        return "(%d, %d)" % (y, x)

那么是否有一个函数或运算符 reinterpret_cast，使得若：

p = Point1(233, 2333)
pid = id(p)
pp = reinterpret_cast(p, Point2)
ppid = id(pp)
pps = str(pp)
t = type(pp)

那么 pid 和 ppid 相同，且 pps 是 '(2333, 233)' 以及 t 是 <class '__main__.Point2'>

# -*- coding:utf-8 -*- class Point1(object): def __init__(self, x, y): (self._x, self._y) = (x, y) def __str__(self): return "(%d, %d)" % (self._x, self._y) class Point2(object): def __init__(self, y, x): (self._x, self._y) = (x, y) def __str__(self): return "(%d, %d)" % (self._y, self._x) def reinterpret_cast_like(instance,cls): newinstance=instance newinstance.__class__=cls return newinstance p1=Point1(1,2) p2=reinterpret_cast_like(p1,Point2) print id(p1),id(p2),p2,type(p2)
执行结果
39093968 39093968 (2, 1) <class '__main__.Point2'> Process finished with exit code 0

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