for循环方式完成列表分区间统计效果报错，求解

list= [
    ...,
    2648, 2648, 2648, 63370, 63370, 425, 425, 120,
    120, 217, 217, 189, 189, 128, 128, 115, 115, 197,
    19752, 152, 152, 275, 275, 1716, 1716, 131, 131,
    98, 98, 138, 138, 277, 277, 849, 302, 152, 1571,
    68, 68, 102, 102, 92, 92, 146, 146, 155, 155,
    9181, 9181, 474, 449, 98, 98, 59, 59, 295, 101,
    ...
]

for i in list:
    if int(i/50)+1 not in dic:
        dic(int(i /50)+1)=list.count(i)
    else:
        dic(int(i /50)+1)+=list.count(i)

我这么写总是报错，我想以 50bp 为一个区间进行统计，即统计长度在 0-50 的频数，50-100 的频数...

我这么写对么，应该怎么写呢?

# code for python3 from itertools import groupby lst= [ 2648, 2648, 2648, 63370, 63370, 425, 425, 120, 120, 217, 217, 189, 189, 128, 128, 115, 115, 197, 19752, 152, 152, 275, 275, 1716, 1716, 131, 131, 98, 98, 138, 138, 277, 277, 849, 302, 152, 1571, 68, 68, 102, 102, 92, 92, 146, 146, 155, 155, 9181, 9181, 474, 449, 98, 98, 59, 59, 295, 101, 5 ] for k, g in groupby(sorted(lst), key=lambda x: x//50): print('{}-{}: {}'.format(k*50, (k+1)*50-1, len(list(g))))
結果:
0-49: 1 50-99: 10 100-149: 15 150-199: 8 200-249: 2 250-299: 5 300-349: 1 400-449: 3 450-499: 1 800-849: 1 1550-1599: 1 1700-1749: 2 2600-2649: 3 9150-9199: 2 19750-19799: 1 63350-63399: 2
我回答過的問題: Python-QA
for i in list i是list中的内容，应该是for I in range(len(list))

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